SQL转金额代码

Create function AtoC

(@ChangeMoney Money ) retuens varchar(100) as

Set Nocount ON

Declare @String1 char(20) Declare @String2 char(30)

Declare @String4 Varchar(100) Declare @String3 Varchar(100) –从原A值中取出的值 Declare @i int –循环变量

Declare @J Int –A的值乘以100的字符串长度 Declare @Ch1 Varchar(100) –数字的汉语读法 Declare @Ch2 Varchar(100) –数字位的汉字读法 Declare @Zero Int –用来计算连续有几个零 Declare @ReturnValue VarChar(100)

Select @ReturnValue = ”

Select @String1 = ‘零壹贰叁肆伍陆柒捌玖’

Select @String2 = ‘万仟佰拾亿仟佰拾万仟佰拾元角分’

Select @String4 = Cast(@ChangeMoney*100 as int)

select @J=len(cast((@ChangeMoney*100) as int))

Select @String2=Right(@String2,@J)

Select @i = 1

while @i<= @j Begin

Select @String3 = Substring(@String4,@i,1)

if @String3<>‘0′ Begin

Select @Ch1 = Substring(@String1, Cast(@String3 as Int) + 1, 1) Select @Ch2 = Substring(@String2, @i, 1) Select @Zero = 0 –表示本位不为零 end

else Begin

If (@Zero = 0) Or (@i = @J – 9) Or (@i = @J – 5) Or (@i = @J – 1) Select @Ch1 = ‘零’

Else

Select @Ch1 = ”

Select @Zero = @Zero + 1 –表示本位为0

–如果转换的数值需要扩大，那么需改动以下表达式 I 的值。 Select Ch2 = ”

If @i = @J – 10 Begin Select @Ch2 = ‘亿’ Select @Zero = 0 end

If @i = @J – 6 Begin Select @Ch2 = ‘万’ Select @Zero = 0 end

if @i = @J – 2 Begin Select @Ch2 = ‘元’ Select @Zero = 0 end

If @i = @J

Select @Ch2 = ‘整’ end

Select @ReturnValue = @ReturnValue + @Ch1 + @Ch2

select @i = @i+1 end

–最后将多余的零去掉

If CharIndex(‘仟仟’,@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, ‘仟仟’,

If CharIndex(‘佰佰’,@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, ‘佰佰’,

If CharIndex(‘零元’,@ReturnValue) <> 0

Select @ReturnValue = Replace(@ReturnValue, ‘零元’,

If CharIndex(‘零万’,@ReturnValue) <> 0

) ) ) ‘仟’‘佰’‘元’Select @ReturnValue = Replace(@ReturnValue, ‘零万’, ‘万’)

If CharIndex(‘零亿’,@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, ‘零亿’, ‘亿’)

If CharIndex(‘零整’,@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue, ‘零整’, ‘整’)

If CharIndex(‘零佰’,@ReturnValue) <> 0

Select @ReturnValue = Replace(@ReturnValue,

If CharIndex(‘零仟’,@ReturnValue) <> 0

Select @ReturnValue = Replace(@ReturnValue,

If CharIndex(‘元元’,@ReturnValue) <> 0 Select @ReturnValue = Replace(@ReturnValue,

return @ReturnValue GO

, , , ) ) ) ‘零佰’‘零’‘零仟’‘零’‘元元’‘元’