发布网友 发布时间:2024-10-24 14:30
共1个回答
热心网友 时间:2024-10-26 18:43
(k+1)!=(k+1)[k(k-1)(k-2).....2x1
=(k+1)k!
(2n)!=2n(2n-1)(2n-2)(2n-3).....[2n-(n-1) ](2n-n)(n-1)(n-2)....2x1
=2n(2n-1)(2n-2)(2n-3)......[2n-(n-1) ]n!
=2n(2n-1)(2n-2)(2n-3)......(n+1)n!
∴ (2n)!/2n!=n(2n-1)(2n-2)...(n+1)